prove that AEB =60°
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Answer is given below
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Step-by-step explanation:
since OC=OD=CD
it is a equilateral triangle
OCD = 60°
let OAC be 'x'
then ACO = x (since OA = OC)
similarly,
DBO = BDO = y
y+x+60=180 ( opposite angles are supplementary)
x+y=120
in triangle ABE
x+y+AEB=180 (A.S.P of triangle)
120+AEB=180
AEB=60°
hence proved
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