Math, asked by rvugtj756, 5 months ago

prove that algebraic numbers are countable in number theory​

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Answered by armaansinghchandan10
0

Answer:

a0zn + a1zn−1 + ··· + an−1z + an = 0. roots, so the set of all possible roots of all polynomials with integer coefficients is a countable union of finite sets, hence at most countable. It is obvious that the set is not finite, so the set of all algebraic numbers are countable.

Answered by keshavnathgupta
6

Answer:

a0zn + a1zn−1 + ··· + an−1z + an = 0. roots, so the set of all possible roots of all polynomials with integer coefficients is a countable union of finite sets, hence at most countable. It is obvious that the set is not finite, so the set of all algebraic numbers are countable.

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