Prove that all rectangle are 90°each.
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A rectangle is defined to be an "equiangular parallelogram". So a rectangle is any four-sided polygon, having two pairs of parallel opposite sides, and four angles which are equal in measure. With this definition, we must still "prove" that each angle measures 90 degrees
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Heya,
here is your answer,
______________
Consider the following figure of rectangle . ( Refer the pic )
The diagonals AC and BD intersect at O.
Thus the vertical angles - angle AOD = angle BOC
Since the line segments AB and CD are parallel lines, and AC is the transversal, then the alternate interior angles
=> angle OCB = angle OAD
Since the line segments AB and CD are parallel lines, and BD is the transversal, then the alternate interior angles
=> angle OBC = angle ODA
The sides AD = BC
Therefore, by Angle-Side-Angle congruence,
=> triangle AOD = triangle BOC
AB and CD are parallel, and BD is a transversal, therefore, the angles
=> angle CDB = angle ABD
Now, Angle ADC = angle ODA + angle BDC
And, Angle ABC = angle OBC + angle ABD
●Thus, Angle ADC = angle ABC
We also know that in a parallelogram, the sum of opposite angles are 180 degrees.
Also , Angle ADC + angle ABC = 180°
Since angle ADC = angle ABC , they have to be equal to 90 degrees each.
Thus, in a rectangle all the angles are 90 degrees.
___________
Hope it helps u !!!
Cheers ☺☺
# Nikky
here is your answer,
______________
Consider the following figure of rectangle . ( Refer the pic )
The diagonals AC and BD intersect at O.
Thus the vertical angles - angle AOD = angle BOC
Since the line segments AB and CD are parallel lines, and AC is the transversal, then the alternate interior angles
=> angle OCB = angle OAD
Since the line segments AB and CD are parallel lines, and BD is the transversal, then the alternate interior angles
=> angle OBC = angle ODA
The sides AD = BC
Therefore, by Angle-Side-Angle congruence,
=> triangle AOD = triangle BOC
AB and CD are parallel, and BD is a transversal, therefore, the angles
=> angle CDB = angle ABD
Now, Angle ADC = angle ODA + angle BDC
And, Angle ABC = angle OBC + angle ABD
●Thus, Angle ADC = angle ABC
We also know that in a parallelogram, the sum of opposite angles are 180 degrees.
Also , Angle ADC + angle ABC = 180°
Since angle ADC = angle ABC , they have to be equal to 90 degrees each.
Thus, in a rectangle all the angles are 90 degrees.
___________
Hope it helps u !!!
Cheers ☺☺
# Nikky
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