Question

prove that all sq root of 1-sin theta /1+Sin theta= sec theta-tan theta​

Answer 1

Enough to show that 1−sinθ1+sinθ=(secθ−tanθ)2(secθ−tanθ)2=sec2θ+tan2θ−2secθtanθ=cos2θ1+cos2θsin2θ−2cosθ1cosθsinθ=cos2θ1+sin2θ−2sinθ=1−sin2θ(1+sinθ)2=(1+sinθ)(1−sinθ)(1+sin2θ)2=1−sinθ1+sinθ.

Step-by-step explanation:

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