Question

Prove that all the sides opposite to equal angles of a triangle are equal.
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jinko aata h wohi bolen fltu bakchodi kr k time ni waste kren ni to report kar die jaoge​

Answer 1

Answer:

ABC is a given triangle with, AB=AC.

To prove: Angle opposite to AB= Angle

opposite to AC (i.e) ∠C=∠B  

Construction: Draw AD perpendicular to BC

∴∠ADB=∠ADC=90°

Proof:  

Consider △ABD and △ACD

AD is common

AB=AC

∴∠ADB=∠ADC=90  

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Hence ∠ABD=∠ACD

∠ABC=∠ACB

∠B=∠C. Hence the proof

Answer 2

Answer:

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