Question

prove that alpha+Beta=-b/a and alphabeta=c/a

Answer 1

Answer:

Step-by-step explanation:

Hope it will help you

Answer 2

Answer:

It is determined by taking generalized quadratic equation.

Step-by-step explanation:

Quadratic equations are the equations of degree two and is in one variable.

It is of the type $f(x)=ax^{2} +bx+c=0$

Assuming the roots of the given quadratic equation be $\alpha ,\beta$.

We know that the sum of roots is the ratio of -coefficient of $x$/coefficient of$x^{2}$.

Hence, $\alpha +\beta =-b/a$

Also, product of roots is ratio of constant term and coefficient of $x^{2}$

So, $\alpha \beta =c/a$

Hence, proved.

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