prove that altitude of an equilateral Triangles are equal
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Answer:
Step-by-step explanation:
Let ABC be the triangle
where AD, BE and CF are the three altitudes on sides BC, AC and AB respectively
In triangle BEC and triangle CFB
angle BEC = angle CFB (both 90o)
angle C = angle B (angles of equilateral triangle are equal)
BC = CB (common)
so, triangle BEC congruent triangle CFB (by AAS congruency)
or BE = CF (by CPCT) -----(1)
similarly, it can be shown that triangle ABE congruent triangle BAD by AAS
and BE = AD (by CPCT) -----(2)
from (1) and (2)
AD = BE = CF
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