Prove that an exterior angle of a cyclic
quadrilateral is congruent to the angle opposite
to its adjacent interior angle.
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Answered by
27
Given:
ABCD is a cyclic quadrilateral.
∠BCE is the exterior angle of ABCD
exterior angle of ABCD.
To prove:
∠BCE = ∠BAD
Proof:
BCE+ BCD = 180°
ABCD is a cyclic quadrilateral.
∠BAD + ∠BCD = 180°
∠BCE + ∠BCD = ∠BAD +∠BCD
∠BCE = ∠BAD
=> ∠BAD = ∠BAD ...hence proved
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amitkumar44481:
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Answered by
5
Answer:
Prove that an exterior angle of a cyclic
quadrilateral is congruent to the angle opposite
to its adjacent interior angle.
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