Prove that andrut 5 irrational.
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Let us assume√5 is rational.
therefore,√5=a/b.
squaring both sides,
5=a^2/b^2.
5b^2=a^2.
Therefore, a^2 is divisible by 5.
therefore, a is also divisible by 5.
a=5c.
squaring both sides,
a^2=25c^2.
but a^2= 5b^2.
THEREFORE, 5b^2=25c^2.
therefore, b^2=5c^2.
hence,b^2 is divisible by 5.
therefore b is also divisible by 5.
therefore ,a and b have common factor.
hence,√5 is irrational.
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