Math, asked by pushpa2429, 1 year ago

prove that angle abc is an isosceles triangle if the altitude ABC from A on BC bisects BC

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Answered by Anonymous
0

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Answered by Sly01
10

In ∆ADB and ∆ADC AD = AD [Common side]

∠APB =∠ ADC [90°] BD = DC [AD bisects BC]

∴∆ADB ≅ ∆ADC [SAS postulate]

∴AB = AC [Corresponding sides]

∴∆ ABC is an isosceles triangle

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