Prove that - angle ACB=ADB=90°
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AB is a common arc of angleACB and
angle ADB.
so,angle ACB=angle ADB.
since,
AB is straight line.
so,
angle o =180.
since,
angle o is centre angle.
since,
we know that centre angle is double then
remaining part of angle of circle.
so,
angle ABC =angle ADB=90.
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