Question

Prove that :Angle AEC =½[m(arc AC)-m(arcBD)]​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

BOD, angle subtended by are BD at center of circle is double the angle at remaining part. ∠BOD = 2∠BCD …..(ii) Adding equation (i) and (ii) ∠AOC + ∠BOD = 2(∠ABC + ∠BCD) ⇒ ∠AOC + ∠BOD = 2∠AEC ⇒ ∠AEC = 1 2 12 [∠AOC + ∠BOD] ⇒ ∠AEC = 1 2 12 [Angle formed at center by CXA angle formed of center by chord DYB]