Question

Prove that angle
BOC+A÷2=90
OB and OC are the bisector​​
Pls dont scam it is important​

Answer 1

Answer:

The solution is very straight forward:

In Triangle OBC the angles

OBC = 1/2 (BAC + BCA)

OCB = 1/2 (BAC + CBA)

By angle sum property

BOC = 180 - 1/2 (BAC +BAC+ BCA + CBA)

BOC = 180 - 1/2 (BAC + 180)

BOC = 180 - 90 - 1/2 BAC

BOC = 90 - 1/2 BAC