Question

prove that angle in a semicircle is a right angle

Answer 1

Answer:

Step-by-step explanation:

Take any point M and N above and below the diameter AB.

Join A to Mand N

Also join B to M and N.

In triangle AMB&ANB

AM=AN (radii of same circle)

BM=BN (radii of same circle)

AB =AB (common side )

:.triangle AMB=~ANB

:./_ABB=/_ANB (C.P.C.T)

:.MANB is a cyclic quadrilateral

:./_ AMB +/_ANB=180°

:.2/_AMB =180°

:./_AMB=90°

HENCE PROVED...