Question

Prove that angle OAB= angle OCD

Answer 1

GIVEN - we have a circle with center O . we draw to equal chords i,e AB and CD . we join OA , OB ,OC and OD.

TO PROVE - The angle subtended by two chords i,e. angle AOB = COD .

PROOF - In triangle's AOB and COD,we have

OA =OC (both are radius of same circle)

OB =OD ( both are radius of same circle)

AB = CD ( given)

so, triangle AOB congruent to triangle COD [as per SSS congruence rule]

Therefore, angle AOB = COD (corresponding angles in congruent triangles are equal )

Hence proved....

Thanks...