Question

prove that Angle opposite to equal sides of an isosceles triangle are equal

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Answer 1

step by step explanation:Given: In isosceles triangle ABC, AB = AC To prove: ∠B = ∠C Construction: Draw the bisector AD of ∠A, which meets BC at D. In ∆BAD and ∆CAD AB = AC (given) ∠BAD = ∠CAD (by construction) AD = AD (common) ∆BAD ≅ ∆CAD (by SAS Rule) => ∠ABD = ∠ACD (CPCT) => ∠B = ∠C