Question

prove that angle opposite to equal sidesof a triangle are equal.​

Answer 1

Answer:

Step-by-step explanation:

The Isosceles Triangle ABC is shown in the figure.

Imagine a perpendicular bisector which divides the triangle into two parts and bisects the base BC at 90 degrees.

Step 1: Prove that triangle ABD is congruent to triangle ACD.

             AB=AC (both are equal because it is an isosceles triangle)

             DB=DC (They are bisected by AD)

             AD=AD (They are common in both the triangles)

Hence, the triangles are congruent to each other by SSS (Side-Side-Side) congruency criterion.

Step 2: If 2 triangles are congruent to each other then all the corresponding angles and sides are equal.

Therefore, we can prove that angle B is equal to angle C by CPCT (Corresponding Parts Of Congruent Triangles).