prove that angle opposites two equal side of a isocelus tringle are equal
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given= ABC is an isosceles triangle with AB=AC
to prove= angle B=angle C
const= draw the bisectore of angle A & let D be the point of intersection of the bisector of angle A and BC
proof=
in triangle ABD and triangle ACD
AB=AC (given)
angle BAD=angle CAD ( AD is bisector of angle A)
AD=AD (common side)
by SAS congruence rule
triangle ABD congruent to triangle ACD
so angle B = angle C( by cpct)
hence proved
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