prove that angle QTR = ½angle QPR
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Explanation:
in triangle PQR
we know that sum of two angle of a triangle is equal to its exterior angle
ang.QPR + ang.PQR = ang.PRS
ang.QPR+ ang.PQT + ang.TQR = ang.TRS + ang.PRT ( QT and TR is the bisecter of ang.PQR and ang.TRS) ang.QPR + 2(ang.TQR) = 2(ang.TRS) angQPR= 2ang.(TQR + TRS) ang.QPR/2 - ang.TQR = ang.TRS ( eq . 1) in tri. TQR ang.TQR + ang.QTR = ang.TRS now from eq 1 ang.TQR + ang.QTR = ang.QPR/2 - ang.TQR ang.QTR = ang.QPR/2
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