Prove that angles apposite to equal sides of an isosceles triangle are equal
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it's equal......... .
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Angles Opposite to Equal Sides of an Isosceles Triangle are Equal
Given: In the isosceles ∆XYZ, XY = XZ.
To prove ∠XYZ = ∠XZY.
Construction: Draw a line XM such that it bisects ∠YXZ and meets the side YZ at M.
Proof
Statement Reason
1. In ∆XYM and ∆XZM 1.
(i) XY = XZ (i) Given.
(ii) XM = XM (ii) Common side.
(iii) ∠YXM = ∠ZXM (iii) XM bisects ∠YXZ.
2. ∆XYM ≅ ∆XZM 2. By SAS criterion
3. ∠XYZ = ∠XZY. (Proved) 3. CPCTC.
.
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