prove that angles opposite to equal side of an isocles triangle are equal
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According to the isosceles triangle theorem, the sides opposite to equal angles of a triangle are equal. Using the Pythagorean theorem, side² = ½base² + height² side² = (½ x 10)² + 24²
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Draw a perpendicular bisector to the base of the isosceles triangle up to the top vertex. The angles opposite to the equal sides can be marked x and y. The perpendicular bisector acts as a common side to the two inner triangles. The hypotenuse of both of the triangles are equal as they are part of the isosceles triangle. So, sin x(Common Side/Equal Side 1) = sin y(Common Side/Equal Side 2). Hence proving, the angle x is equal to y.
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