Question

prove that angles opposite to equal sides of a isosceles triangle are equal ​

Answer 1

Answer:

Take a triangle ABC.

Given: ∆ABC in which AB=AC

To prove: <B= <C

Construction: Draw the bisector of AD of <A which meets BC.

Proof: In ∆ABD and ∆ACD, we have

AB=AC (Given)

<BAD=<CAD (Byconstruction)

AD=AD (Common)

Hence, ∆ABD≈ ∆ACD (By SAS rule)

Thus, <B=<C. (CPCT)

Step-by-step explanation:

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