prove that angles opposite to equal sides of an isosceles
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Here we will prove that in an isosceles triangle, the angles opposite to the equal sides are equal. Given: In the isosceles ∆XYZ, XY = XZ.
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Step-by-step explanation: in an isosceles triangle ABC ie AB =AC
TO PROVE - angle B =angleC
construction draw a bisector of triangle ABC
proof = in triangle BAD and triangle CAD
AB=AC(GIVEN)
ANGLE BAD=ANGLE CAD (BY CONSTRUCTION )
AD=AD (COMMON )
THUS' ANGLE ABD=ANGLE ACD
ANGLE B=ANGLE C
AS all the angles opposite to equal sides are equal
hence verified
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