Math, asked by msofficial904, 3 months ago

Prove that angles opposite to equal sides of an isosceles triangle are equal.​

Answers

Answered by chandandubey8599
3

Answer:

Angles opposite to the equal sides of an isosceles triangle are also equal. Proof: Consider an isosceles triangle ABC where AC = BC. We need to prove that the angles opposite to the sides AC and BC are equal, that is, ∠CAB = ∠CBA.Nov

Answered by archie77
1

Answer:

let there be a triangle ABC, in which AB=AC.

Construct AP bisecting angle A meeting BC at P.

to prove- angles opposite to equal sides of an isosceles triangle are equal

proof-

In ∆ABP and ∆ACP

AP=AP(common)

AB=AC(given])

angle BAP=angle CAP (by construction])

Therefore, ∆ABP congurent ∆ACP by SAS

This implies, angle ABP=angleACP by CPCT

Hence proved

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