prove that "angles opposite to equal sides of and iscoscles triangle are equal
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- Let △ABC be an isosceles triangle such that AB =AC Then we have to prove that ∠B=∠C Draw the bisector AD of ∠A meeting BC in D
- Now in triangles ABD and ACD We have AB=AC (Given)
∠BAD=∠CAD (because AD is bisector of ∠A
AD=AD (Common side)
- Therefore by SAS congruence condition we have
△ABC≅△ACD
⇒∠B=∠C
(Corresponding parts of congruent triangles are equal )
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