prove that angles opposite to the equal sides of a trianagle are equal
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Vandan2080:
dixi70 plz mark on brainlist answer
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so it is obvious that if two sides of triangle are equal so it is isoceles so
const: draw angle bisector of angleA and let the point of intersection of bisector of angleA and BC be D.
to prove:angleB =angleC
proof:in triangle BAD and CAD
AB=BC( given)
Angle BAD=AngleCAD( const)
AD=AD(common)
So triangle BAD Cong. to Triangle CAD
so angle B=angle C by cpct
const: draw angle bisector of angleA and let the point of intersection of bisector of angleA and BC be D.
to prove:angleB =angleC
proof:in triangle BAD and CAD
AB=BC( given)
Angle BAD=AngleCAD( const)
AD=AD(common)
So triangle BAD Cong. to Triangle CAD
so angle B=angle C by cpct
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