Prove that any four vertices of a regular Pentagon lie on a circle
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> Given: A regular pentagon ABCDE.
> To prove: Every set of four vertices of ABCDE is a set of points lying on a circle.
> Proof:
✴️ First we show that the points A, B, C, E lie on a circle.
✴️ Join AC and BE.
✴️ In ∆ABC and ∆BAE, we have:
✴️ AB = BA (common)
✴️ BC = AE (sides of a regular pentagon)
✴️ angle ABC = angle BAE (each equal to 108°)
✴️ Therefore, ∆ABC is congruent to ∆BAE (by SAS congruency rule)
✴️ => angle BCA = angle AEB (by C.P.C.T.)
✴️ Thus, AB subtends equal angle at two points C and E on the same side of AB.
✴️ Therefore, the points A, B, C, E are concyclic
✴️ Similarly, every set of four vertices of pentagon ABCDE is a set of concyclic points.
✨……Hence, PROVED……✨
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