Question

Prove that any number raised to zero is 1?

Answer 1

↑ Here is your answer ↓
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Let any number be 'n',

$n/n = 1$

$n^1/n^1 = 1$

So,

$n^{1-1} = 1$

$n^0 = 1$

Hence proved :)

Answer 2

Hey there,

Let the no. be x

Then x^0=x^(n-n)=(x^n)/(x^n)=1

Hope it helps