Question

prove that any point of the bisector of an angle is equidistant from the arm of the angle​

Answer 1

Step-by-step explanation:

Here we will prove that any point on the bisector of an angle is equidistant from the arms of that angle. Solution: Given OZ bisects ∠XOY and PM ⊥ XO and PN ⊥ OY. To prove PM = PN.

Answer 2

You can use a point on a perpendicular bisector to prove that two segments are congruent. If the point is on the perpendicular bisector of a segment, then it's equidistant from the endpoints of the segment.