Math, asked by chandu3889, 4 months ago

prove that any point of the bisector of an angle is equidistant from the arm of the angle

Answers

Answered by Anonymous

3

Answer:

we need to show BP=CP

in right angles △ABP

sinα=APBP...(i)

in right angled △ACP

sinα=APCP...(ii)

from (i) & (ii)

APBP=APCP

BP=CP

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