Question

prove that any point on bisector of an angle is equidistant from arms of angle​

Answer 1

Step-by-step explanation:

• Here is the answer to your question. EF is the bisector of ∠BOD and ∠COA. R is a point on EF, RP⊥AB and RQ⊥CD. Thus, the perpendiculars drawn from any point on the angle bisector of an angle, to the arms of the angle, are equal.

Answer 2

Step-by-step explanation:

above is your ans....................