Question

prove that any positive odd integer is of the form 6n +1, 6n+3 or 6n + 5 where n is some integer

Answer 1

let 'a' be an positive integer
By Euclid division method
a=bq+r
r=0,1,2,3,4or5
a=6n+r
a=6n+1
a=6n+2
a=6n+3
a=6n+4
a=6n+5
hence, the positive odd integer are 6n+1,6n+3,6n+5

Answer 2

@friend______________