Prove that, any rectangle is a cyclic quadrilateral.
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Given: ABCD is a rectangle. To prove: ABCD is a cyclic quadrilateral. Proof: ⟂XBCD is a rectangle. [Given] ∴ ∠A = ∠B = ∠C = ∠D = 90° [Angles of a rectangle] Now, ∠A + ∠C = 90° + 90° ∴ ∠A + ∠C = 180° ∴ ⟂ABCD is a cyclic quadrilateral. [Converse of cyclic quadrilateral theorem
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