Question

prove that any three consecutive numbers are divisible by 3​

Answer 1

Answer:

Let three consecutive positive integers be n, n + 1 and n + 2. Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2. ∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer. ... So, we can say that one of the numbers among n, n + 1 and n + 2 is always divisible by 3

Answer 2

I hope that this answer is will be right :)