Question

Prove that:[anyone genius there?]
$sin^-^1 \frac{1}{2} +2cot^-^1 \frac{1}{ \sqrt{3} } = \frac{5}{6} \pi$

Answer 1

$Sin^{-1}\frac{1}{2}+2\ Cot^{-1}\frac{1}{\sqrt{3}}\\\\=\frac{\pi}{6}+2*tan^{-1}\sqrt{3}\\\\=\frac{\pi}{6}+2*\frac{\pi}{3}\\\\=\frac{5}{6}\pi$