Question

Prove that ∆AOB and triangle ∆AOC in the following figures are congruent to each other.​

Answer 1

Answer:

∆AOB ≅ ∆AOC (Hypo-side test)

Step-by-step explanation:

Given: Side AB = Side AC

∠AOC =  ∠AOB = 90°

To prove: ∆AOB ≅ ∆AOC

Proof:

In  ∆AOB and triangle ∆AOC

Side AB = Side AC (Give)

Side OA = side OA  (common side)

∠AOC =  ∠AOB = 90° (Given)

∆AOB ≅ ∆AOC (Hypo-side test)

Hence proved.

Answer 2

$\boxed{\large\mathrm{Solution:-}}$

$\mathrm{side \: AB = side \: AC \: \: \: (given)}$

$\mathrm{\angle AOB = \angle AOC \: \: \: (both \: are \: 90°)}$

$\mathrm{ OA = OA \: \: \: (common)}$

Therefore ∆AOB congruent ∆AOC (SAS congruent rule)