Question

prove that ∆ AOB =~∆AOC​

Answer 1

Answer:

in ∆ AOB =~∆AOC

co=bo(given)

angel aob=aoc(given)

ao=ao(common)

Answer 2

Answer:

$\huge{\underline{\underline{Given→}}}$

• $\sf\green{∠AOC=∠AOB=90°}$
• $\sf\green{OC=OB}$

$\huge{\underline{\underline{To\:Prove→}}}$

$\sf\purple{→ΔAOC≈ΔAOB}$

$\huge{\underline{\underline{Proof→}}}$

• $\bold{\underline{\underline{In\:ΔAOC\:and\:ΔAOB→}}}$

1. $\sf\blue{∠AOC=∠AOC(Given)}$
2. $\sf\blue{OC=OB(Given)}$
3. $\sf\blue{AO=AO(Common)}$

$\implies$ ΔAOC≈ΔAOB(By SAS congruence criteria).

$\sf{\boxed{\boxed{\pink{→ΔAOC≈ΔAOB✔}}}}$

$\bold{\underline{\underline{Hence\:Proved✔}}}$

• NOTE$\implies$ Here ≈ means congruent.

HOPE IT HELPS.