prove that AP bisects angle BAC
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is the question part of triangles chapter which chapter is it
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Step-by-step explanation:
first of all join A to P. Voilà you have a right angled triangle. Then two of its sides are already given to be equal, the hypotenuse is same for both of them and for this reason it's equal in both triangles and both have a right angle. therefore they are congruent by RHS congruence rule. and hence you can say that the angle divided by the line AP are equal
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