prove that ap+bq+cr=ar+cq+bp
Answers
Answered by
1
Answer:
Step-by-step explanation:
Attachments:
Answered by
2
Answer:
Since from B, BQ and BP are the tangents to the circle Therefore, BQ = BP ………..(i) Similarly, we can prove that AP = AR …………..(ii) and CR = CQ ………(iii) Adding, AP + BQ + CR = BP + CQ + AR ………(iv) Adding AP + BQ + CR to both sides 2(AP + BQ + CR) = AP + PQ + CQ + QB + AR + CR 2(AP + BQ + CR) = AB + BC + CA Therefore, AP + BQ + CR = (1/2) × (AB + BC + CA) AP + BQ + CR = (1/2) × perimeter of triangle ABC
#1322AnuragKumar
Step-by-step explanation:
Mark as BRAINLIEST
Similar questions