Question

prove that aq=1/2(perimetre of triangleabc)​

Answer 1

Answer:

Step-by-step explanation:

Perimeter of triangle ABC=AB+BC+CA

Now ,we know that the lenght of the tangents drawn from an external point to a circle are equal----

Hence,BM=BQ  and CM=RC--------(i)

Now,

Perimeter of triangle ABC=AB+BC+CA

Perimeter of triangle ABC  =AB+BM+MC+AC

Perimeter of triangle ABC  =AB+BQ+CR+AC   {from (i)}

Perimeter of triangle ABC  =AQ+AR      

Perimeter if triangle ABC=     AQ+AQ   (Because AQ=AR)

Perimeter if triangle ABC=2AQ

HENCE----       aq=1/2(perimetre of triangle abc)​    

Answer 2

Answer:

Step-by-step explanation:

Hope it helps