prove that area and perimeter of square?
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Answer:
Area=side^2
Perimeter =4*side
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hyy dude
So suppose we fix the perimeter of a rectangle as 2(a+b) which side length a and b . Hence , a square with the same perimeter has a side length a+b2 . So we see that the area of the rectangle doen't exceed the area of the square , and the area are equal if and only of a=b .
May this helps you
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