Prove that area of a rhombus is equal to 1/2(product of diagonals)
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since the diagonals of a rhombus bisect each other at 90 degree.
since ABCD is a rhombus. OB=OD and OA=OC.
and ∠AOD= ∠AOB= ∠BOC= ∠COD= 90 degree.
area of ABCD can be divided in four parts.
area(ABCD)= area(ΔAOD)+area (ΔAOB)+ area(ΔBOC) +area(COD)
=1/2(product of diagonals)
since ABCD is a rhombus. OB=OD and OA=OC.
and ∠AOD= ∠AOB= ∠BOC= ∠COD= 90 degree.
area of ABCD can be divided in four parts.
area(ABCD)= area(ΔAOD)+area (ΔAOB)+ area(ΔBOC) +area(COD)
=1/2(product of diagonals)
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