Question

Prove that area of trapezium is 1/2 (sum of parallel sides )×height

Answer 1

Answer:

Step-by-step explanation:

Let the trapezium be ABCD.

Draw one of the diagonals, eg:- BD to form 2 triangles, ABD & BDC.

Since the bases are parallel, the height for both triangles will be same.

Let the ht be h.

Adding areas of both triangles, you get

Area = ABD + BDC = (AB * h) / 2 + (CD * h) / 2 = (AB + CD)*h/2

⇒Proved