Question

prove that as

ar(ΔROS) =ar(ΔPQO) if PS || RQ ​

Answer 1

Answer:

Solution :

______________________

ar(ΔROS) = ar(ΔPQO)

In ΔRos and Pqo

$\frac{ ro}{os} = \frac{pq}{qo}$

when adding 1 in both

ro/os = pq/qo

$\frac{ro}{os} + 1 \: = \: \frac{pq}{qo} + 1$

$\frac{ro + os}{os} = \frac{pq + qo}{qo}$

$\frac{rs}{os} = \frac{po}{qo}$

angle RS= RQ

and PO = PS

hence PS || RQ and ar(ΔROS) = ar(ΔPQO)

Proved