prove that as the number of throw of a fair die increases, each of the probabilities of getting the outcomes 1-6 tends to 1.66..
Answers
Answer:
What increases with time is the cumulative probability of having gotten a 6 during a run of N tosses, as N grows bigger. The more tosses, the higher the probability that at least one of them is a 6.
To be exact, for a fair die the probability of not having gotten a 6 after N tosses is (5/6)^N, so the probability of having gotten at least one is 1-(5/6)^N.
For each individual toss, however, the probability remains the same, which with a fair die means a probability of 1/6 of getting a 6 in that single toss, and a probability of 5/6 of not getting it.
Step-by-step explanation:
Step-by-step explanation:
Outcomes on throw of dice = 1, 2, 4, 5, 6
Even composite numbers = 4, 6
Thus,
Total number of outcomes = 6
Total even composite numbers = 2
Thus,
P(getting an even composite number)
= number of even composites numbers/Total outcomes
=2/6=1/3