Prove that :-
ax(b+c)+bx(c+a)+cx(a+b)=0
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Answer:
abx+acx+bcx+abx+acx+bcx=0
abx+abx+acx+acx+bcx+bcx=0
2abx+2acx+2bcx=0
6a²b²x³=0
a²b²x³=0/6 = 0 (ans)
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