Question

prove that ax2 + bx + c < 0 and a < 0 if and only if b2 - 4ac < 0

Answer 1

Step-by-step explanation:

listed the terms as so: ax2+bx+c≥0≥b2−4ac.

From there I tried to complete the square and ended up with this:

x≥−c/a−−−−√≥(b2/a)−4ac−c/a−−−−−−−−−−−−−−−√.

I'm not quite exactly sure how to show that if a>0, then ax2+bx+c≥0 for all values of x if and