Question

Prove that b+√2 is an irrational number

Answer 1

Answer:

=b+1.414214

Step-by-step explanation:

b+√2

Simplifies to:

Let's simplify step-by-step.

b+1.414214

There are no like terms.

Answer 2

$\huge\bf\red{answer}$

let we assume that b+√2 is a rational number.

we know that,

rational number is written in the form of $\frac{p}{q}$

→b+√2=$\frac{p}{q}$

→√2=$\frac{p}{q}-b$

→√2=$\frac{p+qb}{q}$

since,

→x and y are co-prime , $\frac{p+qb}{q}$ is a rational number

→ and √2 is an irrational number.

→therefore,

★ our contradiction is wrong ★

→ ( b + √2 ) is an irrational number.

→hence,

★proved★