Question

Prove that b + c = 2a. ​

Answer 1

Step-by-step explanation:

Sol: Given that roots are equql.

So,discriminent will be equal to 0. i.e. b2 - 4ac = 0. ⇒ (b - c)2 - 4(a-b)(c - a) = 0 ⇒ b2 - 2bc + c2 - 4ac + 4a2 + 4bc - 4ab = 0 ⇒ b2 + c2- 4ac + 2bc - 4ab + 4a2=0 ⇒ 4a2 + b2 + c2-4ac + 2bc - 4ab = 0 ⇒ (b+c-2a)2 =0 [by algebraic identity-(-a + b + c)2 = a2 + b2 + c2 - 2a - 2ac + 2bc] ⇒ b + c- 2a = 0 ∴ b+c = 2a

Answer 2

Answer:

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