prove that base angle of an isoceles triangle are equal
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Question:-
The correct question is:-Prove that the bisectors of the base angles of an isosceles triangle are equal.
Step-by-step explanation:
solution:-
In △ABC,
AB=AC [Given]
∴∠C=∠B .....(i) [angles opp. to equal sides are equal]
⇒1/2<C = 1/2<B.
∠BCF=∠CBE.......(ii)
Now, In △BCE and △CBF,
=>∠C=∠B [From (i)]
=>∠BCF=∠CBE [From (ii)]
=>BC=BC [Common]
△BCE≅△CBF [AAS]
⇒BE=CF [cpct].
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yes,his answer is right and excellent answer
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